For example, fields deleted with the Delete method are marked for deletion immediately but remain in the collection.
The Update method must be called to actually delete these fields from the provider's collection.
See Section 188.8.131.52, “Inno DB and FOREIGN KEY Constraints”. Records not matching the equijoin from table2 are marked with null.By commenting, you are accepting the DISQUS terms of service.PDF (US Ltr) - 26.9Mb PDF (A4) - 26.9Mb PDF (RPM) - 25.5Mb HTML Download (TGZ) - 6.4Mb HTML Download (Zip) - 6.5Mb HTML Download (RPM) - 5.5Mb Man Pages (TGZ) - 158.5Kb Man Pages (Zip) - 261.7Kb Info (Gzip) - 2.6Mb Info (Zip) - 2.6Mb My SQL Backup and Recovery My SQL NDB Cluster 7.2 My SQL Globalization My SQL Information Schema My SQL Installation Guide My SQL and Linux/Unix My SQL and OS X My SQL Partitioning My SQL Performance Schema My SQL Replication My SQL Restrictions and Limitations Security in My SQL My SQL and Solaris Building My SQL from Source Starting and Stopping My SQL My SQL Tutorial My SQL and Windows clause, are flagged as unsafe for statement-based replication.I am trying to use an update query to update several fields in a table.The following code works fine for one field: UPDATE [Trip Registration] SET [Trip Registration].[Trip1 Confirm] = "C" WHERE (([Trip Registration].[Trip1 Coord])=True); but the problem is that I'd also like the same query to update two other fields (Trip2 Confirm and Trip3 Confirm) using the same kind of criteria.I was not able, using my SQL 4.1.1, to do this as a subquery: UPDATE Groups LEFT JOIN (SELECT Group Id, MIN(Val Within Group) AS base Val FROM Groups GROUP BY Group Id) AS Grp Sum USING (Group Id) SET Val Within Group=Val Within Group-base Val; Csaba Gabor UPDATE Syntax with "on-line" updating value limitations.I had a problem - a had to update a column "rate" but if the existince or new value is greater then 5 this "5" will be finally value in field.Ideal when writing a script is just too much effort.Sometimes you have a lot of processes that could be updating a column value in a table. ID=54321 Here's a workaround for the update/subquery/cant do self table "bug"Senario is, ID 8 has multiple records, only the last (highest) record needs to be changedupdate t1 set c1 = ' NO'where id='8'order by recno desc limit 1I would prefer update t1 set c1=' NO' WHERE ID=8 AND RECNO = (SELECT MAX(RECNO) FROM T1 WHERE ID=8)But that's not currently allowed If you want to update a table based on an aggregate function applied to another table, you can use a correlated subquery, for example: UPDATE table1 SET table1field = (SELECT MAX(table2.table2field) FROM table2 WHERE table1.table1field = table2.table2field)This can be helpful if you need to create a temporary table storing an ID (for, say, a person) and a "last date" and already have another table storing all dates (for example, all dates of that person's orders).Suppose you have a table where each row is associated with a certain group (For example, orders are associated with the customers placing them) where each item WITHIN the group has a distinct number (For example, each person my have a sequence of competition results - each person, therefore, has a 1st, 2nd, 3rd... If you would like to renumber items within their group so that each has the same baseline (say 0), here is an example way to proceed: Create TEMPORARY Table Groups (Id INTEGER AUTO_INCREMENT PRIMARY KEY, Name VARCHAR(31), Group Id VARCHAR(31), Val Within Group INTEGER); INSERT INTO Groups VALUES (null, "Davy", "Boy", 2); INSERT INTO Groups VALUES (null, "Mary", "Girl", 2); INSERT INTO Groups VALUES (null, "Bill", "Boy", 5); INSERT INTO Groups VALUES (null, "Jill", "Girl", -3); INSERT INTO Groups VALUES (null, "Fred", "Boy", 3);# Find the lowest value for each group CREATE TEMPORARY TABLE Group Sum AS SELECT Group Id, MIN(Val Within Group) AS base Val FROM Groups GROUP BY Group Id;# create an index so my SQL can efficiently match ALTER TABLE Group Sum ADD UNIQUE (Group Id);# finally, make the baseline adjustment UPDATE Groups LEFT JOIN Group Sum USING (Group Id) SET Val Within Group=Val Within Group-base Val; SELECT * FROM Groups;# 1 Davy Boy 0# 2 Mary Girl 5# 3 Bill Boy 3# 4 Jill Girl 0# 5 Fred Boy 1#Each group ("Boy", "Girl") now has a (lowest) Val Within Group entry of 0.Notes: That index addition is necessary because on larger tables my SQL would rather die than figure to (internally) index a single column join.